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p2p: read/write handshake concurrently

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This makes it possible to run two base protocols
against each other over a MsgPipe.
This commit is contained in:
Felix Lange 2015-01-03 14:15:43 +01:00
parent 16f417f5af
commit 19d9cc33e4
1 changed files with 12 additions and 11 deletions
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23
p2p/protocol.go
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@ -89,20 +89,26 @@ type baseProtocol struct {
func runBaseProtocol(peer *Peer, rw MsgReadWriter) error {
bp := &baseProtocol{rw, peer}
if err := bp.doHandshake(rw); err != nil {
errc := make(chan error, 1)
go func() { errc <- rw.WriteMsg(bp.handshakeMsg()) }()
if err := bp.readHandshake(); err != nil {
return err
}
// handle write error
if err := <-errc; err != nil {
return err
}
// run main loop
quit := make(chan error, 1)
go func() {
for {
if err := bp.handle(rw); err != nil {
quit <- err
errc <- err
break
}
}
}()
return bp.loop(quit)
return bp.loop(errc)
}
var pingTimeout = 2 * time.Second
@ -193,14 +199,9 @@ func (bp *baseProtocol) handle(rw MsgReadWriter) error {
return nil
}
func (bp *baseProtocol) doHandshake(rw MsgReadWriter) error {
// send our handshake
if err := rw.WriteMsg(bp.handshakeMsg()); err != nil {
return err
}
func (bp *baseProtocol) readHandshake() error {
// read and handle remote handshake
msg, err := rw.ReadMsg()
msg, err := bp.rw.ReadMsg()
if err != nil {
return err
}