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p2p: remove debugging printf calls

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This commit is contained in:
Felix Lange 2015-01-04 00:14:56 +01:00
parent e771873980
commit 3ce2a44053
2 changed files with 1 additions and 6 deletions
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2
p2p/peer.go
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@ -463,7 +463,6 @@ func (r *eofSignal) Read(buf []byte) (int, error) {
func (peer *Peer) PeerList() []interface{} {
peers := peer.otherPeers()
fmt.Printf("address length: %v\n", len(peers))
ds := make([]interface{}, 0, len(peers))
for _, p := range peers {
p.infolock.Lock()
@ -482,6 +481,5 @@ func (peer *Peer) PeerList() []interface{} {
// if ourAddr != nil && !ourAddr.IP.IsLoopback() && !ourAddr.IP.IsUnspecified() {
ds = append(ds, ourAddr)
}
fmt.Printf("address length: %v\n", len(ds))
return ds
}

5
p2p/protocol.go
View file

@ -2,7 +2,6 @@ package p2p
import (
"bytes"
"fmt"
"time"
)
@ -171,8 +170,6 @@ func (bp *baseProtocol) handle(rw MsgReadWriter) error {
case getPeersMsg:
peers := bp.peer.PeerList()
fmt.Printf("get Peers Msg: peers length:%v\n", len(peers))
// this is dangerous. the spec says that we should _delay_
// sending the response if no new information is available.
// this means that would need to send a response later when
@ -186,7 +183,7 @@ func (bp *baseProtocol) handle(rw MsgReadWriter) error {
case peersMsg:
var peers []*peerAddr
if err := msg.Decode(&peers); err != nil {
return newPeerError(errInvalidMsg, "msg %v : %v", msg, err)
return err
}
for _, addr := range peers {
bp.peer.Debugf("received peer suggestion: %v", addr)